Accepted at: Aug, 19, 2024 5:15 p.m.
Author: Brian_BH
Related Deck: 1659128643828
Accepted
Rationale for new note

Unfortunately testable. Maybe not supremely high yield but I definitely got this during one of the AAMC FL's and, to my dismay, I got a version of this on test day.

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Give the two formulas for the average kinetic energy of a gas particle:

KE = \({{c1::(\frac{1}{2})mv^{2} }} = {{c1::(\frac{3}{2})k_{b}T}}\)
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Give the two formulas for the <b>average kinetic energy of a gas particle</b>:<br><br>KE =&nbsp;\({{c1::(\frac{1}{2})mv^{2} }} = {{c1::(\frac{3}{2})k_{b}T}}\)
Extra
kb = Boltzmann constant (1.38x10-23 J/K)
Extra
k<sub>b</sub> = Boltzmann constant (1.38x10<sup>-23</sup> J/K)
Lecture Notes
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Lecture Notes
Missed Questions
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Missed Questions
Pixorize
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Pixorize
Sketchy
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Sketchy
Additional Resources
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Additional Resources
One by one
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One by one
Tags
#AK_MCAT_v2::#Kaplan::General-Chemistry::Ch-08-The-Gas-Phase AnkiHub_Subdeck::AnKing-MCAT::General-Chemistry #AK_MCAT_v2::$Errata::AKadd