Rejected
at 8:59 p.m. Feb, 09, 2025 ]
by
Brian_BH
Author:
m_idso
Rationale for change
Add tag:#AK_MCAT_v2::#UWorld::403505 for question: "What is the pH of the Zn2+(aq) solution in Experiment 1?" becuase it requires you to use the pka to solve for Ka and use the ICE method to solve for the [H3O+] at equilibrium to solve for pH.
Rejection reason
Please feel free to suggest with an appropriate supporting rationale. More information can be found here: https://community.ankihub.net/t/anking-mcat-deck-submission-guidelines/384726
Please let me know if you have any other questions. :-)
No changes in fields
Text
{{c2::Ka}} is the {{c1::acid dissociation}} constant.
Extra
\(\ce{HA_{(aq)} -> H+_{(aq)} + A-_{(aq)}}\) [HA= Strong acid]
\(\ce{K_a = \frac{[\ce{H3O^+}][\ce{A-}]}{[\ce{HA}]}}\)
Ka= acid dissociation constant
Larger Ka: Stronger acid: more product: More H+
An indicator of acid strength.
It is the equilibrium constant corresponding to the dissociation of an acid, HA, into a proton and its conjugate base.
\(\ce{HA_{(aq)} -> H+_{(aq)} + A-_{(aq)}}\) [HA= Strong acid]
\(\ce{HA_{(aq)} + H2O_{(l)} -> H3O+_{(aq)} + A-_{(aq)}}\) [HA= Weak acid]
\(\ce{K_a = \frac{[\ce{H3O^+}][\ce{A-}]}{[\ce{HA}]}}\)
Ka= acid dissociation constant
Larger Ka: Stronger acid: more product: More H+
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