Accepted
at 12:38 a.m. May, 04, 2024
by
Michael_B
Author:
ws1022
Rationale for change
from ch 6 kaplan
No changes in fields
Text
Give the equation for total capacitance when the capacitors are in series:
{{c1::\(\frac{1}{C_{tot}~} = \frac{1}{C_1} + \frac{1}{C_2} + ...\)\(+ \frac{1}{C_n}\)}}
Extra
Photo Credit: Omegatron, CC BY-SA 3.0, via Wikimedia Commons
Parallel capacitance: \(C_{tot} = C_1 + C_2 + ...\)\(+ C_n\)
When capacitors are in series, the total capacitance will always be less than the value of the smallest capacitor
Photo Credit: Omegatron, CC BY-SA 3.0, via Wikimedia Commons
Parallel capacitance: \(C_{tot} = C_1 + C_2 + ...\)\(+ C_n\)
Photo Credit: Omegatron, CC BY-SA 3.0, via Wikimedia Commons
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