Accepted
at 11:38 a.m. Apr, 15, 2024
by
Michael_B
Author:
Brian_BH
Type of change:
New Tags
Rationale for change
QID 400398:
Oh you classic physics questions. Plug-and-play distance/acceleration question.
No changes in fields
Text
\(\Delta x =\) {{c1::\( v_0 \Delta t + \frac{1}{2} a (\Delta t)^2\)}}
Give the equation for displacement as a function of time, initial velocity, and acceleration:
\(\Delta x =\) {{c1::\( v_0 \Delta t + \frac{1}{2} a (\Delta t)^2\)}}
Extra
In a velocity vs time graph, the displacement of a moving object over an interval of time can be derived from the graph by calculating the total area under the curve during that interval.
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